Answer
$b \approx5.03$, $c \approx7.83$, $A =50^\circ$.
Work Step by Step
Given $a=6, B=40^\circ$, we have $b=a\ tanB=6tan40^\circ\approx5.03$, $c=a\ secB=6sec40^\circ\approx7.83$, $A=90^\circ-B=50^\circ$.
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