Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 7 - Applications of Trigonometric Functions - Section 7.1 Right Triangle Trigonometry ; Applications - 7.1 Assess Your Understanding - Page 540: 18

Answer

$sin\theta=\frac{\sqrt 5}{5}$, $cos\theta=\frac{2\sqrt {5}}{5}$, $tan\theta=\frac{1}{2}$, $cot\theta=2$, $sec\theta=\frac{\sqrt {5}}{2}$, $csc\theta=\sqrt 5$.

Work Step by Step

Given $r=\sqrt 5,x=2$, find the missing side $y=\sqrt {5-4}=1$, we have: $sin\theta=\frac{\sqrt 5}{5}$, $cos\theta=\frac{2\sqrt {5}}{5}$, $tan\theta=\frac{1}{2}$, $cot\theta=2$, $sec\theta=\frac{\sqrt {5}}{2}$, $csc\theta=\sqrt 5$.
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