Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 7 - Applications of Trigonometric Functions - Section 7.1 Right Triangle Trigonometry ; Applications - 7.1 Assess Your Understanding - Page 540: 13

Answer

$sin\theta=\frac{\sqrt 3}{2}$, $cos\theta=\frac{1}{2}$, $tan\theta= \sqrt 3 $, $cot\theta=\frac{\sqrt 3}{3}$, $sec\theta=2$, $csc\theta=\frac{2\sqrt 3}{3}$.

Work Step by Step

Given $x=2, r=4$, find the missing side $y=\sqrt {4^2-2^2}=2\sqrt 3$, we have: $sin\theta=\frac{\sqrt 3}{2}$, $cos\theta=\frac{1}{2}$, $tan\theta= \sqrt 3 $, $cot\theta=\frac{\sqrt 3}{3}$, $sec\theta=2$, $csc\theta=\frac{2\sqrt 3}{3}$.
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