Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 7 - Applications of Trigonometric Functions - Section 7.1 Right Triangle Trigonometry ; Applications - 7.1 Assess Your Understanding - Page 540: 15

Answer

$sin\theta=\frac{\sqrt 6}{3}$, $cos\theta=\frac{\sqrt 3}{3}$, $tan\theta=\sqrt 2$, $cot\theta=\frac{\sqrt 2}{2}$, $sec\theta=\sqrt 3$, $csc\theta=\frac{\sqrt 6}{2}$.

Work Step by Step

Given $x=1, y=\sqrt 2$, find the missing side $r=\sqrt {1+2}=\sqrt 3$, we have: $sin\theta=\frac{\sqrt 6}{3}$, $cos\theta=\frac{\sqrt 3}{3}$, $tan\theta=\sqrt 2$, $cot\theta=\frac{\sqrt 2}{2}$, $sec\theta=\sqrt 3$, $csc\theta=\frac{\sqrt 6}{2}$.
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