Answer
$\frac{7}{25}$
Work Step by Step
1. Let $sin^{-1}\frac{3}{5}=t$, we have $sin(t)=\frac{3}{5}$ and $cos(t)=\frac{4}{5}$
2. $cos(2sin^{-1}\frac{3}{5})=cos(2t)=1-2sin^2(t)=1-2(\frac{3}{5})^2=\frac{7}{25}$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.