Answer
See below.
Work Step by Step
$LHS=sec(2\theta)=\frac{1}{cos(2\theta)}=\frac{1}{2cos^2\theta-1}
=\frac{1/cos^2\theta}{2-1/cos^2\theta}
=\frac{sec^2\theta}{2-sec^2\theta}=RHS$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Section 6.6 Double-angle and Half-angle Formulas - 6.6 Assess Your Understanding - Page 519: 51
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