Answer
See below.
Work Step by Step
$LHS=cot(2\theta)\frac{1}{tan(2\theta)}=\frac{1-tan^2\theta}{2tan\theta}
=\frac{1-1/cot^2\theta}{2/cot\theta}
=\frac{cot^2\theta-1}{2cot\theta}=RHS$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Section 6.6 Double-angle and Half-angle Formulas - 6.6 Assess Your Understanding - Page 519: 49
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