Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.6 Double-angle and Half-angle Formulas - 6.6 Assess Your Understanding - Page 519: 48

Answer

See below.

Work Step by Step

$LHS=\frac{cot\theta-tan\theta}{cot\theta+tan\theta} =\frac{cot\theta-tan\theta}{cot\theta+tan\theta}\times\frac{sin\theta cos\theta}{sin\theta cos\theta} =\frac{cos^2\theta-sin^2\theta}{cos^2\theta+sin^2\theta} =\frac{cos(2\theta)}{1}=cos(2\theta)=RHS$
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