Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.6 Double-angle and Half-angle Formulas - 6.6 Assess Your Understanding - Page 519: 64

Answer

See below.

Work Step by Step

$LHS=\frac{cos\theta+sin\theta}{cos\theta-sin\theta}-\frac{cos\theta-sin\theta}{cos\theta+sin\theta} =\frac{(cos\theta+sin\theta)^2-(cos\theta-sin\theta)^2}{(cos\theta-sin\theta)(cos\theta+sin\theta)} =\frac{4sin\theta cos\theta}{cos^2\theta-sin^2\theta} =\frac{2sin(2\theta)}{cos(2\theta)} =2tan(2\theta)=RHS$
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