Answer
See below.
Work Step by Step
$LHS=cot^2\frac{(v)}{2}=\frac{cos^2\frac{(v)}{2}}{sin^2\frac{(v)}{2}}
=\frac{1+cos(v)}{1-cos(v)}=\frac{1/cos(v)+1}{1/cos(v)-1}=\frac{sec(v)+1}{sec(v)-1}=RHS$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Section 6.6 Double-angle and Half-angle Formulas - 6.6 Assess Your Understanding - Page 519: 59
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