Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.6 Double-angle and Half-angle Formulas - 6.6 Assess Your Understanding - Page 519: 58

Answer

See below.

Work Step by Step

$LHS=csc^2\frac{\theta}{2}=\frac{1}{sin^2\frac{\theta}{2}} =\frac{2}{1-cos\theta}=RHS$
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