Answer
See below.
Work Step by Step
$sin(4\theta)=sin[2(2\theta)]=2sin(2\theta)cos(2\theta)=4sin(\theta)cos(\theta)(1-2sin^2\theta)=cos(\theta)(4sin(\theta)-8sin^3\theta)$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Section 6.6 Double-angle and Half-angle Formulas - 6.6 Assess Your Understanding - Page 519: 42
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