Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.4 Trigonometric Identities - 6.4 Assess Your Understanding - Page 497: 89

Answer

See below.

Work Step by Step

$LHS=\frac{1+sin\theta+cos\theta}{1+sin\theta -cos\theta}=\frac{1+sin\theta+cos\theta}{1+sin\theta -cos\theta}\times\frac{1+cos\theta}{1+cos\theta}=\frac{(1+sin\theta+cos\theta)(1+cos\theta)}{sin\theta+sin\theta cos\theta+1-cos^2\theta}=\frac{(1+sin\theta+cos\theta)(1+cos\theta)}{sin\theta+sin\theta cos\theta+sin^2\theta}=\frac{(1+sin\theta+cos\theta)(1+cos\theta)}{sin\theta(1+sin\theta+cos\theta)}=\frac{1+cos\theta}{sin\theta}=RHS$
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