Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.4 Trigonometric Identities - 6.4 Assess Your Understanding - Page 497: 38

Answer

The left side of the equation is equivalent to $\sec^2{x}\tan{x}$ therefore the given equation is an identity. Refer to the solution below.

Work Step by Step

\begin{align} \text{LHS } &= \tan^3{x}+\tan{x} \\[2mm] &= \tan{x}(\tan^2{x}+1) \\[2mm] &= \tan{x} \sec^2{x} \\[2mm] &= \text{ RHS} \end{align}
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