Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.4 Trigonometric Identities - 6.4 Assess Your Understanding - Page 497: 79

Answer

See below.

Work Step by Step

$LHS=\frac{(sec(v)-tan(v))^2+1}{csc(v)(sec(v)-tan(v))}=\frac{sec^2(v)-2sectan(v)+tan^2(v)+1}{csc(v)(sec(v)-tan(v))}=\frac{sec^2(v)-2sectan(v)+sec^2(v)}{csc(v)(sec(v)-tan(v))}=\frac{2sec(v)(sec(v)-tan(v))}{csc(v)(sec(v)-tan(v))}=\frac{2sin(v)}{cos(v)}=2tan(v)=RHS$
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