Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.4 Trigonometric Identities - 6.4 Assess Your Understanding - Page 497: 85

Answer

See below.

Work Step by Step

$LHS=\frac{cos^2\theta-sin^2\theta}{1-tan^2\theta}=\frac{cos^2\theta-sin^2\theta}{1-tan^2\theta}\times\frac{cos^2\theta}{cos^2\theta}=\frac{cos^2\theta(cos^2\theta-sin^2\theta)}{cos^2\theta-sin^2\theta}=cos^2\theta=RHS$
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