Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.4 Trigonometric Identities - 6.4 Assess Your Understanding - Page 497: 68

Answer

See below.

Work Step by Step

$LHS=\frac{sec\theta}{1+sec\theta}=\frac{sec\theta}{1+sec\theta}\times\frac{cos\theta}{cos\theta}=\frac{1}{cos\theta+1}$ $RHS=\frac{1-cos\theta}{sin^2\theta}=\frac{1-cos\theta}{1-cos^2\theta}=\frac{1}{1+cos\theta}=LHS$
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