Answer
See below.
Work Step by Step
$LHS=\frac{sec^2(v)-tan^2(v)+tan(v)}{sec(v)}=\frac{1+tan(v)}{sec(v)}=\frac{1+tan(v)}{sec(v)}\times\frac{cos(v)}{cos(v)}=\frac{cos(v)+sin(v)}{1}=cos(v)+sin(v)=RHS$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Section 6.4 Trigonometric Identities - 6.4 Assess Your Understanding - Page 497: 80
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