Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.3 Properties of the Trigonometric Functions - 5.3 Assess Your Understanding - Page 418: 92



Work Step by Step

As period of cotangent function is $\pi$, then $$\cot \theta=\cot(\theta-\pi)=\cot(\theta-2\pi)$$ Hence, $$\cot \theta+\cot(\theta-\pi)+\cot(\theta-2\pi)=\cot{\theta}+\cot{\theta}+\cot{\theta}=3\cot\theta=3\times(-2)=-6$$
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