Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.3 Properties of the Trigonometric Functions - 5.3 Assess Your Understanding - Page 418: 78



Work Step by Step

$\tan^2{\theta}+1 = \sec^2{\theta}$ By rearranging the equation: $$\sec^2{\theta}-\tan^2{\theta}=1$$ $\therefore \sec^2{18^{\circ}}-\tan^2{18^{\circ}}=\boxed{1}$
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