## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson

# Chapter 5 - Trigonometric Functions - Section 5.3 Properties of the Trigonometric Functions - 5.3 Assess Your Understanding - Page 418: 30

#### Answer

$\text{Quadrant I}$

#### Work Step by Step

$P= (x,y) \text{ is the point on the unit circle corresponding to } \theta$ We have: $\cos{\theta} = x>0$ $\tan{\theta} = \dfrac{y}{x} >0$ Since $x\gt0$ and $\tan{\theta}\gt0$, then $y\gt 0$. Note that points in Quadrant I have $y>0 \text{ and } x>0$. Thusm $\theta \in \text{Quadrant I}$

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