Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.3 Properties of the Trigonometric Functions - 5.3 Assess Your Understanding - Page 418: 79

Answer

$1$

Work Step by Step

$\because \csc{\theta} = \dfrac{1}{\sin{\theta}}$ $\therefore \csc{80^{\circ}} = \dfrac{1}{\sin{80^{\circ}}}$ Hence, $\sin{80^{\circ}} \cdot \csc{80^{\circ}} = \sin{80^{\circ}} \cdot \dfrac{1}{\sin{80^{\circ}}} = \boxed{1}$
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