## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$\text{Quadrant II}$
$P= (x,y) \text{ is the point on the unit circle corresponding to } \theta$ We have $\sin{\theta} = y>0 \text{ and } \cos{\theta} = x<0$. Since points in Quadrant II have $y>0 \text{ and } x<0$, then $\theta \in \text{Quadrant II}$.