Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.3 Properties of the Trigonometric Functions - 5.3 Assess Your Understanding - Page 418: 71

Answer

$0$

Work Step by Step

The tangent is an odd function so $\tan{(- \theta)}= - \tan{\theta}$ Thus, $\tan{\left(- \pi \right) } = - \tan{\left(\pi \right) } = \boxed{0}$
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