Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.3 Properties of the Trigonometric Functions - 5.3 Assess Your Understanding - Page 418: 36


$\tan{\theta}= -\dfrac{4}{3}$ $\csc{\theta} =\dfrac{5}{4}$ $\sec{\theta} =-\dfrac{5}{3}$ $\cot{\theta} =-\dfrac{3}{4}$

Work Step by Step

$\tan{\theta}= \dfrac{\sin{\theta}}{\cos{\theta}}$ $\therefore \tan{\theta}= \dfrac{\dfrac{4}{5}}{-\dfrac{3}{5}}=-\dfrac{4}{3}$ $\csc{\theta} = \dfrac{1}{\sin{\theta}}$ $\therefore \csc{\theta} = \dfrac{1}{\dfrac{4}{5}}=\dfrac{5}{4}$ $\sec{\theta} = \dfrac{1}{\cos{\theta}}$ $\therefore \sec{\theta} = \dfrac{1}{-\dfrac{3}{5}}= -\dfrac{5}{3}$ $\cot{\theta} = \dfrac{1}{\tan{\theta}}$ $\cot{\theta} = \dfrac{1}{-\dfrac{4}{3}}= -\dfrac{3}{4}$
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