Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.3 Properties of the Trigonometric Functions - 5.3 Assess Your Understanding - Page 418: 80



Work Step by Step

$\because \cot{\theta} = \dfrac{1}{\tan{\theta}}$ $\therefore \cot{10^{\circ}} = \dfrac{1}{\tan{10^{\circ}}}$ Hence, $\tan{10^{\circ}} \cdot \cot{10^{\circ}} = \tan{10^{\circ}} \cdot \dfrac{1}{\tan{10^{\circ}}} = \boxed{1}$
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