Answer
Zeros $1,5$.
x-intercept(s) $1,5$.
Work Step by Step
Step 1. Zeros $(x-3)^2-4=0 \longrightarrow x-3=\pm2 \longrightarrow x=1,5$.
Step 2. The x-intercept(s) are the same as the zeros, that is $x=1,5$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 2 - Linear and Quadratic Functions - Chapter Review - Review Exercises - Page 185: 9
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