Answer
Zeros $=-\frac{1}{2}, 1$.
x-intercepts $-\frac{1}{2}, 1$.
Work Step by Step
Step 1. Zeros $-2x^2+x+1=0 \longrightarrow 2x^2-x-1=0 \longrightarrow (2x+1)(x-1)=0 \longrightarrow x=-\frac{1}{2}, 1$.
Step 2. The x-intercepts are the same as the zeros, that is $x=-\frac{1}{2}, 1$.
