Answer
Zeros $-\frac{1}{3}$.
x-intercept $-\frac{1}{3}$.
Work Step by Step
Step 1. Zeros $9x^2+6x+1=0 \longrightarrow (3x+1)^2=0 \longrightarrow x=-\frac{1}{3}$.
Step 2. The x-intercept is the same as the zeros, that is $x=-\frac{1}{3}$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 2 - Linear and Quadratic Functions - Chapter Review - Review Exercises - Page 185: 10
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