Answer
(a) See graph
(b) domain $(-\infty,\infty)$, range $[2,\infty)$.
(c) increasing on $(-\infty,2)$, decreasing on $(2,\infty)$.
Work Step by Step
(a) For $y=(x-2)^2+2$, we can determining that the graph opens up, vertex $(2,2)$, axis of symmetry $x=2$, y-intercept $(0,6)$, x-intercept(s) $none$. See graph
(b) We can determine the domain $(-\infty,\infty)$, range $[2,\infty)$.
(c) We can determine the function is increasing on $(-\infty,2)$, decreasing on $(2,\infty)$.
