Answer
Zeros $\frac{2\pm\sqrt {6}}{2}$.
x-intercepts $\frac{2\pm\sqrt {6}}{2}$.
Work Step by Step
Step 1. Zeros $2x^2-4x-1=0 \longrightarrow x=\frac{4\pm\sqrt {16-4(2)(-1)}}{2(2)}=\frac{2\pm\sqrt {6}}{2}$.
Step 2. The x-intercepts are the same as the zeros, that is $x=\frac{2\pm\sqrt {6}}{2}$.
