Answer
Real zeros $-3,11$
x-intercepts $-3, 11$.
Work Step by Step
Step 1. Real zeros, treat $(x-3)$ as a single unit, $(x-3)^2-2(x-3)=48 \longrightarrow (x-3)^2-2(x-3)-48=0 \longrightarrow (x-3+6)(x-3-8)=0 \longrightarrow x=-3,11$
Step 2. The x-intercepts are the same as the real zeros, that is $ x=-3, 11$.
