Answer
Real zeros $-\frac{1}{2}, \frac{1}{6}$
x-intercept $-\frac{1}{2}, \frac{1}{6}$.
Work Step by Step
Step 1. Real zeros, treat $\frac{1}{x}$ as a single unit, $ (\frac{1}{x})^2-4(\frac{1}{x})-12=0 \longrightarrow (\frac{1}{x}+2)(\frac{1}{x}-6)=0 \longrightarrow x=-\frac{1}{2}, \frac{1}{6}$
Step 2. The x-intercept is the same as the real zeros, that is $ x=-\frac{1}{2}, \frac{1}{6}$.
