Answer
Zeros $-\frac{1}{3},\frac{5}{2}$.
x-intercept(s) $-\frac{1}{3},\frac{5}{2}$.
Work Step by Step
Step 1. Zeros $6x^2-13x-5=0 \longrightarrow (2x-5)(3x+1)=0 \longrightarrow x=-\frac{1}{3},\frac{5}{2}$.
Step 2. The x-intercept(s) are the same as the zeros, that is $x=-\frac{1}{3},\frac{5}{2}$.
