## Precalculus (6th Edition)

$\color{blue}{(5z^2-2x)(4+p)}$
Regroup by grouping the first two terms together and the last two terms together to obtain: $=(20z^2-8x)+(5pz^2-2px)$ Factor out $4$ in the first and $p$ in the second group to obtain: $=4(5z^2-2x)+p(5z^2-2x)$ Factor out $5z^2-2x$ to obtain: $=\color{blue}{(5z^2-2x)(4+p)}$