## Precalculus (6th Edition)

Note that $8=(2^3$. Thus, the given binomial can be written as: $=x^3+2^3$ Factor using the formula $a^3+b^3=(a+b)(a^2-ab+b^2)$ where $a=x$ and $b=2$ to obtain: $=(x+2)(x^2-x(2)+2^2) \\=(x+2)(x^-2x+4)$ Therefore, the answer is Option C.