Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises - Page 43: 10



Work Step by Step

Note that $8=(2^3$. Thus, the given binomial can be written as: $=x^3+2^3$ Factor using the formula $a^3+b^3=(a+b)(a^2-ab+b^2)$ where $a=x$ and $b=2$ to obtain: $=(x+2)(x^2-x(2)+2^2) \\=(x+2)(x^-2x+4)$ Therefore, the answer is Option C.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.