Precalculus (6th Edition)

Published by Pearson

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises - Page 43: 10

C

Work Step by Step

Note that $8=(2^3$. Thus, the given binomial can be written as: $=x^3+2^3$ Factor using the formula $a^3+b^3=(a+b)(a^2-ab+b^2)$ where $a=x$ and $b=2$ to obtain: $=(x+2)(x^2-x(2)+2^2) \\=(x+2)(x^-2x+4)$ Therefore, the answer is Option C.

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