Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises - Page 43: 23



Work Step by Step

The factor $(r+3)$ is common to both terms. Factor out $r+3$ to obtain: $=(r+3)[(5r-6)-(2r-1)] \\=(r+3)[5r-6-2r-(-1)] \\=(r+3)(5r-6-2r+1) \\=(r+3)(3r-5)$
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