#### Answer

Kurt's answer is correct.
The factored form of the given polynomial is $(8a-3)(2a-5)$

#### Work Step by Step

Factor the polynomial by grouping:
Regroup:
$=(16a^2-40a)+(-6a+15)$
Factor out $8a$ in the first and $-3$ in the second group to obtain:
$=8a(2a-5)+(-3)(2a-5)$
Factor out $2a-5$ to obtain:
$=(2a-5)[8a+(-3)]
\\=(2a-5)(8a-3)
\\=(8a-3)(2a-5)$
Thus, Kurt's answer is correct.