## Precalculus (6th Edition)

$\color{blue}{(m^4+3)(2-a)}$
Regroup: $=(2m^4+6)+(-am^4-3a)$ Factor out $2$ in the first and $-a$ in the second group to obtain: $=2(m^4+3)+(-a)(m^4+3)$ Factor out $m^4+3$ to obtain: $(m^4+3)[(2+(-a)] \\=\color{blue}{(m^4+3)(2-a)}$