Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises: 33

Answer

$\color{blue}{(p^2-2)(q^2+5)}$

Work Step by Step

Using the commutative property of addition, the given polynomial is equivalent to: $=p^2q^2-2q^2+5p^2-10$ Regroup by grouping the first two terms together and the last two terms together to obtain: $=(p^2q^2-2q^2)+(5p^2-10)$ Factor out $q^2$ in the first and $-5$ in the second group to obtain: $=q^2(p^2-2)+5(p^2-2)$ Factor out $p^2-2$ to obtain: $=\color{blue}{(p^2-2)(q^2+5)}$
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