Precalculus (6th Edition)

$\color{blue}{(p^2-2)(q^2+5)}$
Using the commutative property of addition, the given polynomial is equivalent to: $=p^2q^2-2q^2+5p^2-10$ Regroup by grouping the first two terms together and the last two terms together to obtain: $=(p^2q^2-2q^2)+(5p^2-10)$ Factor out $q^2$ in the first and $-5$ in the second group to obtain: $=q^2(p^2-2)+5(p^2-2)$ Factor out $p^2-2$ to obtain: $=\color{blue}{(p^2-2)(q^2+5)}$