Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises - Page 43: 27



Work Step by Step

The student was wrong because he was not ave to completely factor the given polynomial. In his answer, $2xy^3(2xy^2-4)$, the terms of the binomial factor have a common factor of $2$. Factoring out the $2$ gives: $=(2xy^3)(2)(xy^2-2) \\=(4xy^3)(xy^2-2)$
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