Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises - Page 43: 25



Work Step by Step

The factor $(m-1)$ is common to both terms. Factor out $m-1$ to obtain: $=(m-1)[2-3(m-1)+2(m-1)^2]$ Distribute $-3$ and square $(m-1)$to obtain: $\\=(m-1)[2-3m+3+2(m^2-2m+1)] \\=(m-1)(5-3m+2m^2-4m+2) \\=(m-1)(2m^2-7m+7)$
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