Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.3 Sum and Difference Identities - 7.3 Exercises - Page 679: 38


$\dfrac {5\pi }{12}$

Work Step by Step

$\cos \alpha =\sin \theta \Rightarrow \alpha +\theta =\dfrac {\pi }{2}\Rightarrow \cos x=\sin \dfrac {\pi }{12}\Rightarrow x+\dfrac {\pi }{12}=\dfrac {\pi }{2}\Rightarrow x=\dfrac {5\pi }{12}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.