Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.3 Sum and Difference Identities - 7.3 Exercises - Page 679: 32

Answer

$\tan 72^{0}$

Work Step by Step

$\alpha +\beta =\dfrac {\pi }{2}\Rightarrow \tan \alpha =\cot \beta \Rightarrow 72^{0}+18^{0}=\dfrac {\pi }{2}\Rightarrow \cot 18^{0}=\tan 72^{0}$
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