Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.3 Sum and Difference Identities - 7.3 Exercises - Page 679: 35



Work Step by Step

$\tan \alpha =\cot \theta \Rightarrow \alpha +\theta =\dfrac {\pi }{2}$ $\tan \theta =\cot \left( 45+2\theta \right) \Rightarrow \theta +45^0+2\theta =\dfrac {\pi }{2}=90^0\Rightarrow \theta =15^0$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.