#### Answer

$\cos \left( -52^{0}14'\right) =\cos \left( 52^{0}14'\right) $

#### Work Step by Step

$\sin 142^{0}14'=\cos \left( 90^{0}-142^{0}14'\right) =\cos \left( -52^{0}14'\right) =\cos \left( 52^{0}14'\right) $

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$\cos \left( -52^{0}14'\right) =\cos \left( 52^{0}14'\right) $

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