Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.3 Sum and Difference Identities - 7.3 Exercises: 26

Answer

$\cos \left( -52^{0}14'\right) =\cos \left( 52^{0}14'\right) $

Work Step by Step

$\sin 142^{0}14'=\cos \left( 90^{0}-142^{0}14'\right) =\cos \left( -52^{0}14'\right) =\cos \left( 52^{0}14'\right) $
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