Answer
$$\theta = {20^ \circ }$$
Work Step by Step
$$\eqalign{
& \sin \theta = \cos \left( {2\theta + {{30}^ \circ }} \right) \cr
& {\text{Use the cofunction identity }}\sin \theta = \cos \left( {{{90}^ \circ } - \theta } \right),{\text{ then}} \cr
& {90^ \circ } - \theta = 2\theta + {30^ \circ } \cr
& {\text{Solving for }}\theta \cr
& {90^ \circ } - {30^ \circ } = 2\theta + \theta \cr
& 3\theta = {60^ \circ } \cr
& \theta = {20^ \circ } \cr} $$