Answer
$tan$
Work Step by Step
$\tan \alpha =\dfrac {1}{\cot \alpha }=\dfrac {1}{\tan \left( 90-\alpha \right) }\Rightarrow \tan 24=\dfrac {1}{\cot 24}=\dfrac {1}{\tan 66}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 7 - Trigonometric Identities and Equations - 7.3 Sum and Difference Identities - 7.3 Exercises - Page 679: 34
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