#### Answer

$\cos 75^{0}$

#### Work Step by Step

$\sin 15^{0}=\cos \left( 90^{\circ }-15^{0}\right) =\cos 75^{0}$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$\cos 75^{0}$

$\sin 15^{0}=\cos \left( 90^{\circ }-15^{0}\right) =\cos 75^{0}$

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