#### Answer

$\sin \dfrac {5\pi }{12}$

#### Work Step by Step

$\cos \dfrac {\pi }{12}=\sin \left( \dfrac {\pi }{2}-\dfrac {\pi }{12}\right) =\sin \dfrac {5\pi }{12}$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$\sin \dfrac {5\pi }{12}$

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